April 2011
Hand out a deck of cards, requesting that a Jack and about a dozen number cards be extracted. Have the selected cards well mixed, and set the rest of the deck aside. Take the chosen cards back and fan through them, face up, joking, "These could be mixed more, I can't help noticing that they are all facing the same way!"
Turn some cards over, and shuffle the quarter deck a little. Fan again, flipping the packet over if necessary, until you spot the Jack. Say, "The goal is to make this Knight vanish into the packet so that none of us knows where he is. There's a twist: you get to make him disappear, by thumbing off between one and six cards, and flipping them over like this, as many times as you like."
Suppose the Jack is face-up in position four from the top of the fan: thumb off four, five or six cards as a unit, and then flip it over, replacing the cards on top of the rest of the packet, now reversed. The Jack will no longer be visible if the cards are fanned. Now turn the entire packet over and repeat: thumbing off and flipping over the same number of cards as before. Explain that you think of this thumb and flip routine as "twisting" and also that it must always be done to each end of the packet, hence the turning over and repeating using the same number of cards.
Continue, "It doesn't matter if you know where the Knight is, as long as I don't have any idea. I want you to use this die here to randomize things. Roll it, and whatever number comes up, twist that many cards, as explained before. Then turn the whole packet over and twist the same number of cards again. Then roll the die once more, and use that number to determine how many cards you twist, twice as did just now. I'll watch the first time so that I know you've got the hang of it, then I'll turn away and you can do it as often as you wish. When you're convinced that the Knight is well and truly lost, fan the cards to make sure he's not face-up, then hand the packet to me."
Turn away as promised, and have the die rolled and double twisting done quite a few times. Finally, you turn back, and are handed the packet. Fanning it quickly, you have no difficulty correctly identifying the Knight.
The above is an impromptu version of a more interesting effect which we shortly discuss in some detail. Essentially, it's based on a twist on the triple and quadruple dealing of the first Card Colm (October 2004), in the related double dealing incarnation studied here last time around (February 2011). For the sake of completeness, we also consider the hitherto unmentioned Low-Down Single Dealing.
Before exploring the deal-free alternative, let's review the basic move. Start with a packet of n cards, and pick a number k such that n/2 ≤ k ≤ n. Have k cards dealt out into a pile, thus reversing their order, holding the cards low down, and have the remaining n - k cards dropped on top as a unit. This is the deal about this DALHDROP (Deal At Least Half and Drop the Rest On Top) move:
As discussed in the first Card Colm (October 2004), the last two claims above can be seen by studying the sequence of images here:
This illustrates the case n = 13 and k = 8, where the packet after successive DALHDROP moves is represented by vertical stacks of grey panels, from left to right, the panels initially being in decreasing order of brightness.
We now explain how to have a similar effect on a packet of cards without any dealing and dropping at all. The key is the observation that:
There are other ways of achieving the same goal, such as reversing the order of the cards in the smaller subpacket!
Applying DALHDROP once to nine cards from twelve face-up cards arranged Ace, 2, 3, ..., 6, 7, ..., Jack, Queen, from top to bottom, yields 10, Jack, Queen, 9, 8, 7, 6, ..., Ace.
What if, instead of doing that, one simply thumbed off the top nine cards as a unit, flipped it over, and tucked it underneath the remaining three cards? The only difference between the final outcome here and that earlier would be that nine of the cards would now be facing the opposite way.
Here's another alternative with even less thumbing off: once again start with a face-up arrangement Ace, 2, 3, ..., 6, 7, ..., Jack, Queen, from top to bottom. Turn the whole packet over, so it's now face-down, and then thumb off just three cards, as a unit, holding them to one side. Take the nine cards underneath and bring them forward, turning them over as a unit, and dropping them on top of the three thumbed off. Or one could thumb off three cards, flip them over as a unit, and replace them on top of the remaining nine--perhaps turning the whole packet over at the end! Ignoring card orientation issues, either of these yields similar results. In what follows, we'll apply such alternative moves to both ends of the packet, so we can dispense with any initial or final turning over of the whole packet.
The video clips below illustrate in the case n = 13 and k = 8. We use Clubs, in ascending order. The first video clip shows the standard DALHDROP move applied to face-down cards. The second shows the new move, applied to the same cards, where five cards are thumbed off instead of eight being dealt out. The third clip shows how one can make it less obvious what is really going on: by starting with the cards in some desirable order, but having some face-down and others face-up.
Click on the images below to see the clips.
The key here is to: thumb off and flip at most half of the cards, maybe we should call this the TOFAMH (Thumb Off and Flip At Most Half) move.
Now we are ready to try our first application. Start with all thirteen Clubs, where Ace = 1, Jack = 11, etc. Pair them as follows: 2 with 7, then 3 with 9, then 4 with 10, and 5 with 8, and finally 6 with the Jack. Note that each number is paired with its multiplicative inverse, modulo 13. Pair the Ace and Queen too. Arrange these twelve cards in a "palindromic stack," with the King in the middle. The elements of each pair as just assigned are equidistant from the center. Turn over one card in each pair so that it faces the other way. Hence, the 6 is as far from the center card as the Jack is, and is facing the other way.
No matter how much "double twisting" is done, as explained earlier, the Jack and 6 will remain equidistant from the King, and facing opposite ways, so that all you need to do upon reclaiming the cards is look for the face-up 6, and the Jack (or Knight) will be in the corresponding position, either counted out from the middle or in from the end.
Furthermore, every face-down card—and there will be six or seven overall—can also be speedily identified. This suggests options such as having people pick two or three of those, instead of playing the game of Twisting the Knight Away.
There is no particular significance to the multiplicative inverse pairings above, it just has the advantage of being both easy to remember and hard for the average audience to spot any pattern.
For the impromptu version we started with, you just need to note the card which is the same distance from the center as the Jack at the outset. Of course it must be facing the opposite way; another quick shuffle and a glance at both sides of the resulting fan should do the trick.