Reconsider the mean proportionals *x* and *y* of *a* and 2*a: a*:*x* = *x*:*y* = *y*:2*a*. With the help of modern analytic geometry, we see that this is equivalent to solving simultaneously two of *x*^{2} = *ay*, *y*^{2} = 2*ax*, and *xy* = 2*a*^{2}. You should notice immediately that *x*^{2} = *ay* and *y*^{2} = 2*ax* are equations of parabolae, and *xy* = 2*a*^{2} is the equation of a hyperbola. Solving these equations simultaneously is equivalent to intersecting these conics.

Taking the second and third equations and solving them simultaneously gives *x*^{3} = 2*a*^{3}, so a cube of side *x* has double the volume of a cube of side *a*.

Was Menaechmus the first to use conic sections? In the same work by Eutocius we have a description of Eratosthenes' (3rd century B.C.) solution to the problem of finding two mean proportionals. In regards to the merits of his own solutions, Eratosthenes is quoted as saying "Do not seek to do the difficult business of the cylinders of Archytas [another method of solution], or to cut the cone in the triads of Menaechmus, or to produce any such curved form in lines as is described by the divine Eudoxus." **[14, **p. 297**]**. Based on this quote, it would seem that the "triads of Menaechmus" refers to the **three** conic sections (we have not yet discussed the ellipse at this point). Because of this Menaechmus is given credit for discovering all three conic sections.

Did Menaechmus actually take sections of a cone? We do not know. The parabola and hyperbola can be constructed pointwise using the geometry of Menaechmus' time. The pointwise generation of the parabola looks something like the graph below.

It is not too hard to imagine the circles in this picture as horizontal slices of a slanted cone **[11, **p. 117**]**.

Scholars have taken up this idea and have given probable constructions of conic sections based on sections of a right angled cone **[5, **pp. 1-4**]** **[9, **pp. 111-116**]**. We take up this discussion in the next sections.