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Van Schooten's Ruler Constructions - Second solution to Problem II

Author(s): 
C. Edward Sandifer

Another way:  Find, as before, away from AC, any point C, and draw from it through the points A and B straight lines CAD, CBE, and make AD equal to AC and BE equal to BC.  Then join DB, AE, and let them intersect at F.  I say that if FC is made, it will bisect AB at G.

 

Branch point

            The other eight problems

C. Edward Sandifer, "Van Schooten's Ruler Constructions - Second solution to Problem II," Loci (August 2010)

Dummy View - NOT TO BE DELETED