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Van Schooten's Ruler Constructions - Solution to Problem VIII

Author(s): 
C. Edward Sandifer

Problem VIII:   Above a given straight line AB, to construct an equilateral triangle.

 

Construction:  Cut AB by the second problem, into two equal parts at C, and from C, above AB, by the 5th problem, erect a perpendicular CF and locate on it DC equal to AC or CB.  Draw DB and above that construct, as in the 5th problem, a perpendicular to DE at D, and equal to DC, and join EB.  I say that if CF is made equal to BE and the triangle AF, FB is made, then the triangle AFB is equilateral.

Branch point:     

         The other eight problems

                          

Dummy View - NOT TO BE DELETED