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World Class Sprints - Parameter Values

Author(s): 
David Smith

We turn now to the question of appropriate values for the parameters 20 years after Keller's work. The following tables record 1993 world-class performances in the 100 meter sprint, separately for men and women. Each table shows "split times" for 30, 60, 80, and 100 meters.

 
Men's Split Times for 100 M Sprint,
1993 World Championships
 
 Name  30 m  60 m  80 m  100 m
 Linford Christie  3.85  6.45  8.15  9.87
 Andre Carson  3.83   6.43  8.15  9.92
 Dennis Mitchell  3.82  6.46  8.22  9.99
 Carl Lewis  3.95  6.59  8.30  10.02
 

 
Women's Splits for 100 M Sprint,
1993 World Championships
 
 Name  30 m  60 m  80 m  100 m
 Gail Devers  4.09  6.95  8.86  10.82
 Merlene Ottey  4.13  6.98  8.87  10.82
 Gwen Torrence  4.14  7.00  8.92  10.89
 Irina Privalova  4.09  7.00  8.96  10.96
 
 

To illustrate the meanings of split times -- and the possibility that Keller's parameters are outdated -- we show the men's split times in the following figure, along with possible model distance functions. Christie's data (fastest) are shown as solid circles, and Lewis's (slowest) as open diamonds. The broken curve shows the distance function you calculated in Part 2 with Keller's parameters. The solid curve shows a possibly better fit -- with a faster terminal velocity.

  1. Calculate average split times for men for each of the distances. (We will take up the women's data later.) We call these times T1, T2, T3, T4, corresponding respectively to the distances D1 = 30, D = 60, D3 = 80, D4 = 100.
  2. Each (time,distance) pair gives you numbers to substitute into your distance formula to get equations that involve only A and b. If you take ratios of two distances, say D1 and D2, you will have an equation that involves only b. Why? If the corresponding times are T1 and T2, explain why the resulting equation is

Before we charge ahead to find a value of b from the displayed equation, we make a few observations about this equation and its relation to the modeling process. 

  • When we have two parameters to determine from the data, such as A and b, there is an advantage in having an equation that involves only one of them. It is much easier to solve equations in one unknown than in two.

  • Once we have a reasonable value for b, we can use that in the time-distance relation to find a corresponding value of A.

  • Unless our model is a perfect fit to the data -- which hardly ever happens -- we will get a different determination of b from each pair of (time,distance) pairs. If these values are reasonably close to each other (i.e., consistent), it may make sense to average them. If not, we should rethink whether the model is really appropriate for the data.

  • We obtained the displayed equation by taking the ratio of D1 to D2 -- but we would get the same information about b if we had taken the ratio of D2 to D1. That is, the same value of b would satisfy both equations. Thus, there is no point in taking ratios both ways.

  • Given four (time,distance) pairs to choose from,

    (T1,D1), (T2,D2), (T3,D3), (T4,D4),

    there are six different ways to pair them up so the first subscript is smaller than the second: (1,2), (1,3), (1,4), (2,3), (2,4), (3,4). Thus, we get six possibly different determinations of b from our men's data.

Before we tackle the problem of finding a numerical value for b, we will look at the problem graphically to see if it makes sense to proceed.

  1. Plot the difference between left-hand and right-hand sides of the equation displayed in step 2, as a function of b, to isolate and estimate a value for b.

  2. Copy and edit your plotting command to produce corresponding plots for the other five combinations of subscripts. Plot all six graphs together to see if they give relatively consistent information about b. Record your best estimate of b from the visual information.

  3. Solve the equation in step 2 for b, using the first two (time,distance) pairs for the men. (The solution may take a little time -- be patient.) Then vary the (time,distance) pairs several times to get your best estimate of the parameter b for the men.

  4. Explain why A can now be found from the equation

 

  1. Solve for the parameter A for the men, again using several choices of (time,distance) pair to get your best estimate.

  2. As a check on your work, plot your distance function for men together with the data for one of the men (or the average data, if you prefer).

  3. Repeat steps 1, 3, 4, 5, and 7 to estimate the parameters b and A for women.

  4. Repeat step 8 with the women's distance function and data.

David Smith, "World Class Sprints - Parameter Values," Loci (December 2004)

JOMA

Journal of Online Mathematics and its Applications

Dummy View - NOT TO BE DELETED