A mouse is at the top of a poplar tree 60 *braccia* high, and a cat is on the ground at its foot. The mouse descends \(\frac{1}{2}\) a *braccia* a day and at night it turns back \(\frac{1}{6}\) of a *braccia*. The cat climbs one *braccia* a day and goes back \(\frac{1}{4}\) of a *braccia* each night. The tree grows \(\frac{1}{4}\) of a *braccia* between the cat and the mouse each day and it shrinks \(\frac{1}{8}\) of a *braccia* every night. In how many days will the cat reach the mouse?

*Summa de arithmetica*, Luca Pacioli, 1494

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The answer is: the cat reaches the mouse during the 63rd day