Given 9900 *drachmai*, let it be divided into four parts; let the second be greater than the first by \(\frac{1}{7}\) of the first; let the third exceed the sum of the first two by 300 *drachmai*, and let the fourth exceed the sum of the first three by 300 *drachmai*; find the numbers.

University of Michigan Papyrus Collection (inv. 620), c. 150 CE

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The answer is: 1050, 1200, 2550 and 5100 *drachmai*