Example 12: A problem leading to the case “squares = numbers” [Rosen 1831, 55]
A square, four of the roots of which multiplied by five of its roots produce twice the square, with a surplus of thirty-six dirhems; then the solution is: that you multiply four roots by five roots, which gives twenty squares, equal to two squares and thirty-six dirhems.
Remove two squares from the twenty on account of the other two. The remainder is eighteen squares, equal to thirty-six dirhems. Divide now thirty-six dirhems by eighteen; the quotient is two, and this is the square.
Continue to Example 13.
Back to Overview of al-Khwārizmī’s More Complicated Problems.